Post by Hayley on Oct 25, 2010 18:45:28 GMT -5
Ok, Hayley, you are going to try and help me study for my algebra test on Thursday.
Why do I have to help you? Isnt that what Kourtney and Griffin are for?
Yes, but Kourt and Griff arent here. Theyre at their own houses tonight.
[/color]Hmph. What good friends.
Just shut up and help me! Its the first test of the quarter.
...Fine.
Okay, so we've been learning about Venn Diagrams.
Isnt that what you use to compare stuff with? Why the heck are you using it for math?
Yes, it can be used to compare things, but in algebra its almostthe same. Math Venn Diagrams are comparing different sets of information. So if their was a question that said for example "90 students were surveyed on what type of pets they have. 33 have dogs, 27 have cats, 12 have both, and how many have a dog nor a cat and how many people have (a) dog/s or (a) cat/s?"
Well thats easy! Even I can figure that out. 33+27+12=72. 90-72=18. So 18 people dont have pets. And to answer your second question, 87 people have dogs or cats. That was too easy, Real Hayley.
Ha, I got you. You did get the first part right, but not the second. You dont cound the people with both because I said OR. And the people with both have a dog AND a cat. So the real answer is 60 people have a dog or a cat. In the diagram, you would have the rectangle with the two intertwined circles. Dog would be above one and "Cat" would be above the other. 33 would be in the dogs only circle, 27 would be in the cats only circle, 12 would be in the intertwined part, and 18 would be on the inside of the rectangle but not inside a circle. The 18 without a dog or cat are still part of the universal set but dont have a dog or cat.
Psh. Gimme the next topic.
Umm okay. Lets see...-flips through math book-
Ooo, I like that one!
Alright, whatever wou say Hales.
Yep! It is whatever I say.
Dont make me put you back in that vent system with Gavin and Jasmine!
....
Oh, you picked a good one for once. This isnt on thetest, but you probably need help with it anyway.
Hey! Im offended by that!
That was the point of saying it, stupid.
Soo those equations whose names I can never remember. I like these, but hate them because I dont like graphing.
Isnt that what District 13 did? Graph?
No, they mined for graphite. But lets get back on topic.
So you have this equation: 3x-5<4x+3<9+3x. Do you know what to do, smart-mouth?
Yes, Sarcastic, I actually do. First you subtract 3x from each side so then it looks like this: -5<x+3<9. Then you subtract 3 from each side to get the 3 from next to the x and then you have -8<x<7. And thats your answer.
But can you put it in the terms of AND? like x<? and x>?
Maybe...lets see. x<7 AND x>-8.
Good job Hayley! Since you got that one right, I shall let you be free for the rest if the night.
Whoo-hoo! Free at last! See ya sucker! -runs in opposite direction-[/size][/color]
Why do I have to help you? Isnt that what Kourtney and Griffin are for?
Yes, but Kourt and Griff arent here. Theyre at their own houses tonight.
[/color]Hmph. What good friends.
Just shut up and help me! Its the first test of the quarter.
...Fine.
Okay, so we've been learning about Venn Diagrams.
Isnt that what you use to compare stuff with? Why the heck are you using it for math?
Yes, it can be used to compare things, but in algebra its almostthe same. Math Venn Diagrams are comparing different sets of information. So if their was a question that said for example "90 students were surveyed on what type of pets they have. 33 have dogs, 27 have cats, 12 have both, and how many have a dog nor a cat and how many people have (a) dog/s or (a) cat/s?"
Well thats easy! Even I can figure that out. 33+27+12=72. 90-72=18. So 18 people dont have pets. And to answer your second question, 87 people have dogs or cats. That was too easy, Real Hayley.
Ha, I got you. You did get the first part right, but not the second. You dont cound the people with both because I said OR. And the people with both have a dog AND a cat. So the real answer is 60 people have a dog or a cat. In the diagram, you would have the rectangle with the two intertwined circles. Dog would be above one and "Cat" would be above the other. 33 would be in the dogs only circle, 27 would be in the cats only circle, 12 would be in the intertwined part, and 18 would be on the inside of the rectangle but not inside a circle. The 18 without a dog or cat are still part of the universal set but dont have a dog or cat.
Psh. Gimme the next topic.
Umm okay. Lets see...-flips through math book-
Ooo, I like that one!
Alright, whatever wou say Hales.
Yep! It is whatever I say.
Dont make me put you back in that vent system with Gavin and Jasmine!
....
Oh, you picked a good one for once. This isnt on thetest, but you probably need help with it anyway.
Hey! Im offended by that!
That was the point of saying it, stupid.
Soo those equations whose names I can never remember. I like these, but hate them because I dont like graphing.
Isnt that what District 13 did? Graph?
No, they mined for graphite. But lets get back on topic.
So you have this equation: 3x-5<4x+3<9+3x. Do you know what to do, smart-mouth?
Yes, Sarcastic, I actually do. First you subtract 3x from each side so then it looks like this: -5<x+3<9. Then you subtract 3 from each side to get the 3 from next to the x and then you have -8<x<7. And thats your answer.
But can you put it in the terms of AND? like x<? and x>?
Maybe...lets see. x<7 AND x>-8.
Good job Hayley! Since you got that one right, I shall let you be free for the rest if the night.
Whoo-hoo! Free at last! See ya sucker! -runs in opposite direction-[/size][/color]
